8.1.4.7 Packet Tracer – Subnetting Scenario

  • 07/07/2018 17:08
  • 427

8.1.4.7 Packet Tracer – Subnetting Scenario

Packet Tracer – Subnetting Scenario (Answer Version)

Answer Note: Red font color or gray highlights indicate text that appears in the Answer copy only. Optional activities are designed to enhance understanding and/or to provide additional practice.

Topology

8.1.4.7 Packet Tracer – Subnetting Scenario

8.1.4.7 Packet Tracer – Subnetting Scenario

Addressing Table

Device Interface IP Address Subnet Mask Default Gateway
R1 G0/0 192.168.100.1 255.255.255.224 N/A
G0/1 192.168.100.33 255.255.255.224 N/A
S0/0/0 192.168.100.129 255.255.255.224 N/A
R2 G0/0 192.168.100.65 255.255.255.224 N/A
G0/1 192.168.100.97 255.255.255.224 N/A
S0/0/0 192.168.100.158 255.255.255.224 N/A
S1 VLAN 1 192.168.100.2 255.255.255.224 192.168.100.1
S2 VLAN 1 192.168.100.34 255.255.255.224 192.168.100.33
S3 VLAN 1 192.168.100.66 255.255.255.224 192.168.100.65
S4 VLAN 1 192.168.100.98 255.255.255.224 192.168.100.97
PC1 NIC 192.168.100.30 255.255.255.224 192.168.100.1
PC2 NIC 192.168.100.62 255.255.255.224 192.168.100.33
PC3 NIC 192.168.100.94 255.255.255.224 192.168.100.65
PC4 NIC 192.168.100.126 255.255.255.224 192.168.100.97

Objectives

Part 1: Design an IP Addressing Scheme

Part 2: Assign IP Addresses to Network Devices and Verify Connectivity

Scenario

In this activity, you are given the network address of 192.168.100.0/24 to subnet and provide the IP addressing for the network shown in the topology. Each LAN in the network requires enough space for, at least, 25 addresses for end devices, the switch and the router. The connection between R1 to R2 will require an IP address for each end of the link.

Part 1: Design an IP Addressing Scheme

Step 1: Subnet the 192.168.100.0/24 network into the appropriate number of subnets.

  1. Based on the topology, how many subnets are needed? 5
  2. How many bits must be borrowed to support the number of subnets in the topology table? 3
  3. How many subnets does this create? 8
  4. How many usable hosts does this create per subnet? 30
    • Note: If your answer is less than the 25 hosts required, then you borrowed too many bits.
  5. Calculate the binary value for the first five subnets. The first subnet is already shown.
Net 0: 192 . 168 . 100 . 0 0 0 0 0 0 0 0

Net 1: 192 . 168 . 100 . ___ ___ ___ ___ ___ ___ ___ ___

Net 1: 192 . 168 . 100 . 0 0 1 0 0 0 0 0

Net 2: 192 . 168 . 100 . ___ ___ ___ ___ ___ ___ ___ ___

Net 2: 192 . 168 . 100 . 0 1 0 0 0 0 0 0

Net 3: 192 . 168 . 100 . ___ ___ ___ ___ ___ ___ ___ ___

Net 3: 192 . 168 . 100 . 0 1 1 0 0 0 0 0

Net 4: 192 . 168 . 100 . ___ ___ ___ ___ ___ ___ ___ ___

Net 4: 192 . 168 . 100 . 1 0 0 0 0 0 0 0

f.  Calculate the binary and decimal value of the new subnet mask.

11111111.11111111.11111111. ___ ___ ___ ___ ___ ___ ___ ___

11111111.11111111.111111111. 1 1 1 0 0 0 0 0

255 . 255 . 255 . ______

255 . 255 . 255 . 224

g.     Fill in the Subnet Table, listing the decimal value of all available subnets, the first and last usable host address, and the broadcast address. Repeat until all addresses are listed.

Note: You may not need to use all rows.

Subnet Table

Subnet Number Subnet Address First Usable Host Address Last Usable Host Address Broadcast Address
0 192.168.100.0 192.168.100.1 192.168.100.30 192.168.100.31
1 192.168.100.32 192.168.100.33 192.168.100.62 192.168.100.63
2 192.168.100.64 192.168.100.65 192.168.100.94 192.168.100.95
3 192.168.100.96 192.168.100.97 192.168.100.126 192.168.100.127
4 192.168.100.128 192.168.100.129 192.168.100.158 192.168.100.159
5 192.168.100.160 192.168.100.161 192.168.100.190 192.168.100.191
6 192.168.100.192 192.168.100.193 192.168.100.222 192.168.100.223
7 192.168.100.224 192.168.100.225 192.168.100.254 192.168.100.255
8
9
10

Step 2: Assign the subnets to the network shown in the topology.

  1. Assign Subnet 0 to the LAN connected to the GigabitEthernet 0/0 interface of R1: 192.168.100.0 /27
  2. Assign Subnet 1 to the LAN connected to the GigabitEthernet 0/1 interface of R1: 192.168.100.32 /27
  3. Assign Subnet 2 to the LAN connected to the GigabitEthernet 0/0 interface of R2: 192.168.100.64 /27
  4. Assign Subnet 3 to the LAN connected to the GigabitEthernet 0/1 interface of R2: 192.168.100.96 /27
  5. Assign Subnet 4 to the WAN link between R1 to R2: 192.168.100.128 /27

Step 3: Document the addressing scheme.

Fill in the Subnet Table using the following guidelines:

  1. Assign the first usable IP addresses to R1 for the two LAN links and the WAN link.
  2. Assign the first usable IP addresses to R2 for the LANs links. Assign the last usable IP address for the WAN link.
  3. Assign the second usable IP addresses to the switches.
  4. Assign the last usable IP addresses to the hosts.

Part 2: Assign IP Addresses to Network Devices and Verify Connectivity

Most of the IP addressing is already configured on this network. Implement the following steps to complete the addressing configuration.

Step 1: Configure IP addressing on R1 LAN interfaces.

Step 2: Configure IP addressing on S3, including the default gateway.

Step 3: Configure IP addressing on PC4, including the default gateway.

Step 4: Verify connectivity.

You can only verify connectivity from R1, S3, and PC4. However, you should be able to ping every IP address listed in the Addressing Table.

Suggested Scoring Rubric

Note: The majority of points are allocated to designing and documenting the addressing scheme. Implementation of the addresses in Packet Tracer is of minimal consideration.

Activity Section Question Location Possible Points Earned Points
Part 1: Design an IP Addressing Scheme Step 1a 1
Step 1b 1
Step 1c 1
Step 1d 1
Step 1e 4
Step 1f 2
Complete Subnet Table Step 1g 10
Assign Subnets Step 2 10
Document Addressing Step 3 40
Part 1 Total 70
Packet Tracer Score 30
Total Score 100

Bình luận

About Us

CCNA v5 Answers, CCNA v5 Blog, CCNA 5 Blog, CCNA Blog

Articles

Our Contacts